Re: scanf function

[Greg Heckenberg <GorgeousGreg@hotmail.com>]

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I'm not too sure where you can find it. . . check your compiler
documentation.  MSDN might be a good resource.  I haven't looked into it too
much though :)

~Greg


----- Original Message -----
From: russ <nupc@nupc.org>
To: <gameprogrammer@topica.com>
Sent: Saturday, March 31, 2001 12:17 PM
Subject: Re: scanf function


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> THANK you!  that did the trick.  do you know a place online that i can
> read about this scanf() function, i would like to understand better the
> first argument string of this function (eg. "%c%*c")  thanks!
>
> russ
>
>
> > scanf("%c%*c", &c);
> >
> > That should do it.
> >
> > The * is an assignment suppression, so it reads in the '\n', but doesn't
> > store it to a variable.
> > You might want to experiment w/ fflush(stdin) too.
> >
> > Hope this helps :)
> >
> > ~Greg
> >
> > > hi gang,
> > >
> > > ok, here's the general code:
> > >
> > > do
> > > {
> > > char choice;
> > > printf( "Enter 'a', 'q', or 'f': " );
> > > scanf( "%c" &choice );
> > > printf( "Your choice was: %c", choice );
> > > if( choice == 'a' ) ...
> > > if( choice == 'f' ) ...
> > > }while (choice != 'q' )
> > > printf( "Finished" );
> > >
> > > the problem is when i go through this loop it goes through it twice
> > > because on scanf() it takes the char as input AND the newline (ie
'\n').
> > >
> > > so an example output would be:
> > >
> > > Enter 'a', 'q', or 'f': e
> > > Your choice was: e
> > > Enter 'a', 'q', or 'f':       <- the input is the newline from the "e"
> > > Your choice was:              <- output is the newline ("\n")
> > >
> > > Enter 'a', 'q', or 'f': q
> > > Finished
> > >
> > > now how can i have the input be JUST the "e" and not the newline "\n"?
> > > thanks for anyhelp, this problem has given me much fuss.
> > >
> > > russ
>
>
>

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