Re: scanf function

[russ <nupc@nupc.org>]

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THANK you!  that did the trick.  do you know a place online that i can
read about this scanf() function, i would like to understand better the
first argument string of this function (eg. "%c%*c")  thanks!

russ


> scanf("%c%*c", &c);
>
> That should do it.
>
> The * is an assignment suppression, so it reads in the '\n', but doesn't
> store it to a variable.
> You might want to experiment w/ fflush(stdin) too.
>
> Hope this helps :)
>
> ~Greg
>
> > hi gang,
> >
> > ok, here's the general code:
> >
> > do
> > {
> > char choice;
> > printf( "Enter 'a', 'q', or 'f': " );
> > scanf( "%c" &choice );
> > printf( "Your choice was: %c", choice );
> > if( choice == 'a' ) ...
> > if( choice == 'f' ) ...
> > }while (choice != 'q' )
> > printf( "Finished" );
> >
> > the problem is when i go through this loop it goes through it twice
> > because on scanf() it takes the char as input AND the newline (ie '\n').
> >
> > so an example output would be:
> >
> > Enter 'a', 'q', or 'f': e
> > Your choice was: e
> > Enter 'a', 'q', or 'f':       <- the input is the newline from the "e"
> > Your choice was:              <- output is the newline ("\n")
> >
> > Enter 'a', 'q', or 'f': q
> > Finished
> >
> > now how can i have the input be JUST the "e" and not the newline "\n"?
> > thanks for anyhelp, this problem has given me much fuss.
> >
> > russ

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